Question

Methanol (CH3OH) is manufactured by the reaction of carbon monoxide with hydrogen in the presence of a Cu/ZnO/Al2O3 catalyst: CO(g) + 2H2(g) ? CH3OH(g) Starting with an equilibrated mixture, what happens to the quantity of methanol in the mixture if CO(g) is removed from the container (at constant temperature and pressure), and why? Select one: a. decreases, because the forward reaction initially unchanged while the reverse reaction speeds up b. increases, because the reaction quotient Q is initially smaller than the equilibrium constant K c. increases, because the reverse reaction initially slows down compared to the forward reaction d. no change, because once a reaction is at equilibrium, it cannot be changed e. decreases, because the reaction quotient Q is initially larger than the equilibrium constant K

          Methanol (CH3OH) is manufactured by the reaction of carbon monoxide with hydrogen in the presence of a Cu/ZnO/Al2O3 catalyst: CO(g) + 2H2(g) ? CH3OH(g)

Starting with an equilibrated mixture, what happens to the quantity of methanol in the mixture if CO(g) is removed from the container (at constant temperature and pressure), and why?

Select one:
a. decreases, because the forward reaction initially unchanged while the reverse reaction speeds up
b. increases, because the reaction quotient Q is initially smaller than the equilibrium constant K
c. increases, because the reverse reaction initially slows down compared to the forward reaction
d. no change, because once a reaction is at equilibrium, it cannot be changed
e. decreases, because the reaction quotient Q is initially larger than the equilibrium constant K

Methanol (CH3OH) is manufactured by the reaction of carbon monoxide with hydrogen in the presence of a Cu/ZnO/Al2O3 catalyst: CO(g) + 2H2(g) ? CH3OH(g)

Starting with an equilibrated mixture, what happens to the quantity of methanol in the mixture if CO(g) is removed from the container (at constant temperature and pressure), and why?

Select one:
a. decreases, because the forward reaction initially unchanged while the reverse reaction speeds up
b. increases, because the reaction quotient Q is initially smaller than the equilibrium constant K
c. increases, because the reverse reaction initially slows down compared to the forward reaction
d. no change, because once a reaction is at equilibrium, it cannot be changed
e. decreases, because the reaction quotient Q is initially larger than the equilibrium constant K

Added by Virginia R.

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