00:01
Horizontal distance ac is 3 meters.
00:04
The vertical height between joints.
00:07
A, e, and d is 4 meters.
00:13
The angle theta, a joint b is 30 degrees.
00:25
We've solved for support reactions.
00:29
Some of force in the x direction equal to zero.
00:44
Ax is going to be equal to zero because there's no horizontal for loads.
00:48
Sum of forces in the y direction is zero that's going to be a plus d y is equal to 10 plus 16 so that's going to be 26 kiloons and then the sum of moments about a or equal to zero so 16 times 3 minus di times 6 is equal to 0 so, the i equals 16 times 3 over 6.
01:32
So that's 8 kiloons.
01:36
Therefore, a, y is equal to 26 minus 8.
01:40
That's 18 kiloons.
01:43
So the reactions, x is 0, and y is 18, dy is 8.
02:14
So for join a, f a .a .e, coside 30, there is a y therefore fae equals to 20 .78 kiloons in the x direction fab fae sine 30 so fab 10 .39 kilonutons that's for joint a joint b or sorry joint d fd c .e.
03:17
Cosign 30.
03:19
D .y.
03:21
Therefore, fde.
03:24
It's 9 .24 kiloons...