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mework 3.1 < Question 1, 3.1.12 > HW Score: 38.89%, 7 of 18 points Points: 0 of 1 Save K A car has 12,500 miles on its odometer. Say the car is driven an average of 40 miles per day. Choose the model that expresses the number of miles N that will be on its odometer after x days. Choose the correct answer below. A. N(x) = 40 - 12,500 B. N(x) = 40x + 12,500 C. N(x) = 12,500x + 40 D. N(x) = -40x + 12,500

Name: mework 31 question 1 3112 hw score 3889 7 of 18 points points 0 of 1 save k a car has 12500 miles on its odometer say the car is driven an average of 40 miles per day choose the model that e 44357
Uploaded: 2023-02-17T17:14:55-08:00
Channel: Nicole Hoffman
Description: mework 31 question 1 3112 hw score 3889 7 of 18 points points 0 of 1 save k a car has 12500 miles on its odometer say the car is driven an average of 40 miles per day choose the model that e 44357

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< Question 1, 3.1.12 >
HW Score: 38.89%, 7 of 18 points
Points: 0 of 1
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A car has 12,500 miles on its odometer. Say the car is driven an average of 40 miles per day. Choose the model that expresses the number of miles N that will be on its odometer after x days.
Choose the correct answer below.
A. N(x) = 40 - 12,500
B. N(x) = 40x + 12,500
C. N(x) = 12,500x + 40
D. N(x) = -40x + 12,500

mework 31 question 1 3112 hw score 3889 7 of 18 points points 0 of 1 save k a car has 12500 miles on its odometer say the car is driven an average of 40 miles per day choose the model that e 44357

Added by Kyle C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Nicole Hoffman

02/17/2023

Step 1

Initial mileage = 12,500 miles. Daily mileage increase = 40 miles per day. Show more…

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mework 3.1 < Question 1, 3.1.12 > HW Score: 38.89%, 7 of 18 points Points: 0 of 1 Save K A car has 12,500 miles on its odometer. Say the car is driven an average of 40 miles per day. Choose the model that expresses the number of miles N that will be on its odometer after x days. Choose the correct answer below. A. N(x) = 40 - 12,500 B. N(x) = 40x + 12,500 C. N(x) = 12,500x + 40 D. N(x) = -40x + 12,500