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Elementary Statistics a Step by Step Approach
6 months ago
So for this problem, for part A we're actually going to find the T. Score, that's because the standard deviation is unknown, and when it's unknown, we use the student's T distribution. So substituting the values for X. Bar for mu for the standard deviation of our sample and a sample size of 19, The numerator becomes a negative one and then using my calculator -1, divided by 19. Wait five, divided by the square root Of 19, because that's the sample size. So we end up with a T. score of -0.22. Now the 2nd 1 is a Z score because we do know the standard deviation of our population. So the numerator starts out the same, But now we use 19.3 and our new sample size is 13, So it's still negative one. Using my calculator -1, divided by standard deviation divided by the square root of the population. And so we have a Z score of negative 0.186, which would round to negative 0.19.
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