Question

16 of 25 Find the general solution to the differential equation. y'' - 3y' - 4y = 0 $\bigcirc$ y = $c_1e^t + c_2e^{4t}$ $\bigcirc$ y = $c_1e^{-t} + c_2e^{4t}$ $\bigcirc$ y = $c_1e^{-3t} + c_2e^{-4t}$ $\bigcirc$ y = $c_1e^{3t} + c_2e^{4t}$

          16 of 25
Find the general solution to the differential equation.
y'' - 3y' - 4y = 0
$\bigcirc$ y = $c_1e^t + c_2e^{4t}$ $\bigcirc$ y = $c_1e^{-t} + c_2e^{4t}$ $\bigcirc$ y = $c_1e^{-3t} + c_2e^{-4t}$ $\bigcirc$ y = $c_1e^{3t} + c_2e^{4t}$

16 of 25
Find the general solution to the differential equation.
y” - 3y' - 4y = 0
◯ y = c1e^t + c2e^4t ◯ y = c1e^-t + c2e^4t ◯ y = c1e^-3t + c2e^-4t ◯ y = c1e^3t + c2e^4t

Added by Alan C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

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Solved by Expert Patricia Taylor

Step 1

First, we can simplify the equation by combining like terms: -6y = 0. Show more…

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Find the general solution to the differential equation y - 3y - 4y = 0. Oy = ce + cze^(-4t) Oy = ce + ce^4t Oy = ce^(-3t) + ce^(-4t) y = c3t + ce^4t

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16 of 25 Find the general solution to the differential equation. y'' - 3y' - 4y = 0 $\bigcirc$ y = $c_1e^t + c_2e^{4t}$ $\bigcirc$ y = $c_1e^{-t} + c_2e^{4t}$ $\bigcirc$ y = $c_1e^{-3t} + c_2e^{-4t}$ $\bigcirc$ y = $c_1e^{3t} + c_2e^{4t}$

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