00:02
Hi, here in the first part of this given problem, at the top of the loop in the roller coaster radius is 15 .0 meter and at that topmost point, downward acceleration being experienced, this is 1 .50 times of the acceleration due to gravity.
00:46
So using an expression for the sentry -petal acceleration, a is equal to v square by r and plugging in 1 .50 into g for a or we can say this is 9 .8 also is equal to v square.
01:06
We have to find v divided by r which is 15 .0 meter so this v will be given by the square root of 1 .50 into 9 .8 into 15 means this is 220 .1 .5 this is so the speed at the topmost point comes out to be equal to 14 .8 meter per second answer for the first part of this given problem here.
01:48
Now in the second part of the problem, we have to find the height from which it should start so that it may complete this loop.
02:01
So we have an expression for that height.
02:07
So the height from where, from which it should start coming down.
02:22
That is given as 5 by 2 times of the radius of the loop.
02:28
So here it will be 5 by 2 times 1.
02:32
Sorry, this is 15.
02:35
So finally this height comes out to be equal to 37 .5 meter...