The standard form of an ellipse is $\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1$, where $(h, k)$ is the center of the ellipse.
In this case, $a^2 = 49$ and $b^2 = 4$.
Therefore, $a = \sqrt{49} = 7$ and $b = \sqrt{4} = 2$.
Since $a > b$, the major axis is along
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