Question

molar mass$_{Al}$ = 26.98 g/mol molar mass$_{HCl}$ = 36.45 g/mol molar mass$_{AlCl3}$ = 133.33 g/mol molar mass$_{H2}$ = 2.00 g/mol If 19.5 grams of aluminum completely react to form hydrogen gas according to the equation given, how much hydrogen gas is produced?

Name: molar massal 2698 gmol molar masshcl 3645 gmol molar massalcl3 13333 gmol molar massh2 200 gmol if 195 grams of aluminum completely react to form hydrogen gas according to the equation g 16873
Uploaded: 2024-03-01T19:13:42-08:00
Duration: 1 min 59 s
Channel: Oluwapelumi Kolawole
Description: molar massal 2698 gmol molar masshcl 3645 gmol molar massalcl3 13333 gmol molar massh2 200 gmol if 195 grams of aluminum completely react to form hydrogen gas according to the equation g 16873

          molar mass$_{Al}$ = 26.98 g/mol
molar mass$_{HCl}$ = 36.45 g/mol
molar mass$_{AlCl3}$ = 133.33 g/mol
molar mass$_{H2}$ = 2.00 g/mol
If 19.5 grams of aluminum completely react to form hydrogen gas according to the equation given, how much hydrogen gas is produced?

molar massal 2698 gmol molar masshcl 3645 gmol molar massalcl3 13333 gmol molar massh2 200 gmol if 195 grams of aluminum completely react to form hydrogen gas according to the equation g 16873

Added by Carla E.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Oluwapelumi Kolawole

03/01/2024

Step 1

The balanced equation is: $$2Al + 6HCl \rightarrow 2AlCl_3 + 3H_2$$ Show more…

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molar mass$_{Al}$ = 26.98 g/mol molar mass$_{HCl}$ = 36.45 g/mol molar mass$_{AlCl3}$ = 133.33 g/mol molar mass$_{H2}$ = 2.00 g/mol If 19.5 grams of aluminum completely react to form hydrogen gas according to the equation given, how much hydrogen gas is produced?