Question

molecule is \( 1,13 \AA \). Locate the centre of mass of the molecule relative to carbon atom. [0.602 A ] 2. Two bodies of masses 2 g and 10 g have position vectors \( 3 \hat{i}+2 \hat{j}-\hat{k} \) and \( \hat{i}-\hat{j}+3 \hat{k} \) respectively. Find the position vector and distance of C.M. from the ongin. \[ \left[\frac{1}{6}(18 \hat{i}-3 \hat{j}+14 \hat{k}) ; 2.73 \text { units }\right] \]

          molecule is \( 1,13 \AA \). Locate the centre of mass of the molecule relative to carbon atom.
[0.602 A ]
2. Two bodies of masses 2 g and 10 g have position vectors \( 3 \hat{i}+2 \hat{j}-\hat{k} \) and \( \hat{i}-\hat{j}+3 \hat{k} \) respectively. Find the position vector and distance of C.M. from the ongin.
\[
\left[\frac{1}{6}(18 \hat{i}-3 \hat{j}+14 \hat{k}) ; 2.73 \text { units }\right]
\]

molecule is 1,13 Å. Locate the centre of mass of the molecule relative to carbon atom.
[0.602 A ]
2. Two bodies of masses 2 g and 10 g have position vectors 3 î+2 ĵ-k̂ and î-ĵ+3 k̂ respectively. Find the position vector and distance of C.M. from the ongin.

[(1)/(6)(18 î-3 ĵ+14 k̂) ; 2.73 units ]

Added by John D.

Physics Principles with Applications

Douglas C. Giancoli 6th Edition

Chapter 7

Instant Answer

Solved by Expert Vishal Gupta

08/14/2020

Step 1

The distance between the atoms is \(1.13 \, \text{Å}\). Show more…

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molecule is \( 1,13 \AA \). Locate the centre of mass of the molecule relative to carbon atom. [0.602 A ] 2. Two bodies of masses 2 g and 10 g have position vectors \( 3 \hat{i}+2 \hat{j}-\hat{k} \) and \( \hat{i}-\hat{j}+3 \hat{k} \) respectively. Find the position vector and distance of C.M. from the ongin. \[ \left[\frac{1}{6}(18 \hat{i}-3 \hat{j}+14 \hat{k}) ; 2.73 \text { units }\right] \]