5 mm on the screen. The distance from the slit to the screen (L) is 2.60 m. We can use the small angle approximation, where \( \tan(\theta) \approx \sin(\theta) \approx \frac{y}{L} \).
\[
\theta \approx \frac{y}{L} = \frac{16.5 \times 10^{-3} \text{ m}}{2.60
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