Given:
Speed of light in vacuum, \(v_1 = 3.00 \times 10^8 \, m/s\)
Refractive index of water, \(n = 1.33\)
Using the formula: \(v = \frac{v_1}{n}\)
Substitute the values to get:
\(v = \frac{3.00 \times 10^8}{1.33} = 2.25 \times 10^8 \, m/s\)
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