More than 21 of of car crashes occur within 2 miles of the motoriats home. Express the null and altereative hypotheses in symbelic form for twis claim (enter as a percentage). \[ \begin{array}{l} H_{0}: P \square \square \\ H_{1}: P \square \square \end{array} \] Use the following codes to teter the follswing symbal: > sater > Cuater a Fanter I
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Close to home ~ A 2008 study by the National Highway Traffic Safety Administration reported that 47% of all car crashes occur within 5 miles of the crashing person's home. Jill is skeptical of this report and believes that the true proportion of such crashes is more than 47%. Jill collects a random sample of 171 crashes and finds that 89 have occurred within 5 miles of the crashing person's home. Round all numeric answers to 4 decimal places. 1. What are the null and alternative hypotheses? Ho: p = 0.4700 Ha: p > 0.4700 2. Calculate the null standard error for this hypothesis test. .038167 3. What is the test statistic for this hypothesis test? 1.32229 4. Calculate the p-value. .093036 5. Based on the p-value, we have Some evidence against the null hypothesis. 6. Which of the statements below are correct interpretations of the p-value? You should choose all that are correct interpretations. A. The p-value is the probability of obtaining a sample result at least as or more in favor of the alternative hypothesis if the null hypothesis is true. B. The p-value is the probability that the null hypothesis is true. C. If we repeat the hypothesis test many times, the p-value is the proportion of times our test statistic will be close to the expected value of the null distribution. D. The p-value is the proportion of times in repeated sampling that the alternative hypothesis is true. E. The p-value tells us that the null model is compatible with the data.
Madhur L.
Close to home ~ A 2008 study by the National Highway Traffic Safety Administration reported that 47% of all car crashes occur within 5 miles of the crashing person's home. Jill is skeptical of this report and believes that the true proportion of such crashes is more than 47%. Jill collects a random sample of 186 crashes and finds that 97 have occurred within 5 miles of the crashing person's home. Round all numeric answers to 4 decimal places. 1. What are the null and alternative hypotheses? Ho: p = 0.4700 Ha: p > 0.4700 2. Calculate the null standard error for this hypothesis test. 0.0348 3. What is the test statistic for this hypothesis test? 1.4812 4. Calculate the p-value. 5. Based on the p-value, we have Little evidence against the null hypothesis. 6. Which of the statements below are interpretations of the p-value? You should choose all that are correct interpretations. A. The p-value is the probability that the null hypothesis is true. B. If we repeat the hypothesis test many times, the p-value is the proportion of times our test statistic will be close to the expected value of the null distribution. C. The p-value is the proportion of times in repeated sampling that the alternative hypothesis is true. D. The p-value is the probability of obtaining a sample result at least as or more in favor of the alternative hypothesis if the null hypothesis is true. E. The p-value tells us that the null model is compatible with the data.
Adi S.
In a study of 11,000 car crashes, it was found that 5,720 of them occurred within 5 miles of home. Use a 0.05 significance level to test the claim that more than 50% of car crashes occur within 5 miles of home. Fill in the requested information. Step 1 H0: p ≤ 0.50 Ha: p > 0.50 Step 2 Significance level: α = 0.05 Step 3 Test: Values for each required entry on calculator: p-value: Step 4 Decision: Reason
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