9. Most recent tests and calculations estimate at the \( 95 \% \) confidence level that the maternal ancestor to all living humans call mitochondrial Eve lived \( 273,000 \pm 177,000 \) years ago. What is meant by \( 95 \% \) confidence" in this coatext? a. A confidence iaterval of the true age of mitochondrial Eve has been calculated using zascores of \( \pm \) \( 1.96 \) b. A coafidence interval of the true age of mitochondrial Eve has been calculated using \( t \)-scores consistent with \( \mathrm{df}=\mathrm{n}-1 \) and tail probabilities of \( \pm 0.025 \). c. There is a \( 0.95 \) probability that mitochondrial Eve lived between \( 96.000 \) and 450,000 years ago. d. If 20 random samples of data are obtained by this method, and a \( 95 \% \) confidence interval is calculated from each, then the true age of mitochondrial Eve will be in 19 of these intervals. (e.) \( 95 \% \) of all random samples of data obtained by the method will yleld intervals that capture the true age of mitochondrial Eve.
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This option talks about using z-scores of ±1.96, which is consistent with a 95% confidence interval. However, it does not mention anything about the age range of mitochondrial Eve. b. This option talks about using t-scores and degrees of freedom, which are used Show more…
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Most recent tests and calculations estimate at the $95 \%$ confidence level that mitochondrial Eve, the maternal ancestor to all living humans, lived $138,000 \pm 18,$ ooo years ago. What is meant by "95\% confidence" in this context? (A) A confidence interval of the true age of mitochondrial Eve has been calculated using $z$ -scores of ±1.96 . (B) A confidence interval of the true age of mitochondrial Eve has been calculated using $t$ -scores consistent with $d f$ $=n-1$ and tail probabilities of $\pm 0.025 .$ (C) There is a 0.95 probability that mitochondrial Eve lived between 120,000 and 156,000 years ago. (D) If 20 random samples of data are obtained by this method and a $95 \%$ confidence interval is calculated from each, the true age of mitochondrial Eve will be in 19 of these intervals. (E) Of all random samples of data obtained by this method, $95 \%$ will yield intervals that capture the true age of mitochondrial Eve.
Inference for Quantitative Data: Means
Quiz 26
Rochan B.
Ages of mothers at first birth were recorded for a random sample of 14 mothers in England. A sign test is to be used to test the hypothesis that the median age of mothers at first birth is 30. It is found that the number of values lying above the assumed value for the population median is 3 and the number of values lying below the assumed median is 11. The following table gives the probability distribution for a random sample of size 14. Number of [+]s, x: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 P(x|[+]): 0.000, 0.001, 0.006, 0.022, 0.061, 0.122, 0.183, 0.209, 0.183, 0.122, 0.061, 0.022, 0.006, 0.001, 0.000 Use the table to calculate the p-value for this hypothesis test. Hence select the answer that gives the correct conclusion for this test. For convenience, Unit 6 Table 10 (Subsection 5.1) is reproduced here. p value | Rough interpretation p > 0.10 | Little evidence against the hypothesis 0.10 ≥ p > 0.05 | Weak evidence against the hypothesis 0.05 ≥ p > 0.01 | Moderate evidence against the hypothesis 0.01 ≥ p > 0.001 | Strong evidence against the hypothesis 0.001 ≥ p | Very strong evidence against the hypothesis
Adi S.
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