0:00
All right, we have two questions.
00:01
Question three says that earth is a distance of about 150 billion meters from the sun, and the sun has a mass of 1 .99 from 10 to the 30th kilograms, and earth has a mass of 5 .98 times 10 to the 24th kilograms, and it takes earth a total time of basically 31 .5 million.
00:31
Seconds to complete one revolution on some that's a year of course so we want to find the magnitude of the for part a we want to find the centripetal acceleration of earth and first let's find the speed so the speed is just going to be 2 pi r over t and this should come out to about 29 that we'll write this is 2 .98 times 10 to the fourth meters for second.
00:59
And so that's going to give us a centripetal acceleration of about 5 .92 times 10 to the negative third meters per second squared because remember centripetal acceleration is v squared over r.
01:18
So that's our acceleration.
01:20
Using that, we want to find the force of gravity that the sun exerts on earth.
01:24
So this will be the mass of earth times this acceleration.
01:28
And so if we plug those numbers in, we get something like 3 .54 times 10 to the 22nd newton's.
01:35
And then part c asks us, what is the sun's centripetal acceleration? so the sun's acceleration is going to be the same force we just calculated, but divided by the mass of the sun instead.
01:49
It's basically newton's third law.
01:52
So this is 1 .78 times 10 to the negative 8 meters per second...