MRAD110 - Chapter 11 Math Worksheet
Please refer to the formulas in Chapter 11 of your textbook. Formulas will not be provided on the exam. Complete each problem and show your calculations on your completed assignment.
The Inverse Square Law
\[
\frac{\mathrm{l}_{\mathrm{f}}}{\left(\mathrm{l}_{\mathrm{g}}\right)}=\frac{\left(\mathrm{c}_{3}\right)^{2}}{\left(\mathrm{c}_{\mathrm{l}}\right)^{2}}
\]
Inverse square (Refer to the Inverse Square Law Formula on p. 138 in the text)
a. The intensity of radiation at \( 40^{\prime \prime} \) SID is equal to 400 mR . What is the radiation intensity at a distance of \( 72^{\prime \prime} \) ?
Radiation intensity at \( 72^{\prime \prime}= \) \( \qquad \)
b. The intensity of radiation at \( 56^{\prime \prime} \) SID is equal to 200 mR . Calculate the radiation intensity at a distance of \( 40^{\prime \prime} \).
Radiation intensity at \( 40^{\prime \prime}= \) \( \qquad \)
mAs/distance compensation (Refer to_page 139 in the text)
a. Optimal exposure to the IR is achieved at 25 mAs and \( 40^{\prime \prime} \) SID. Calculate the new mAs at a distance of \( 72^{\prime \prime} \). Show your work below:
New mAs at \( 72^{\prime \prime}= \) \( \qquad \)
b. You have completed an image at 50 mAs and \( 72^{\prime \prime} \). Calculate the new mAs at a distance of \( 56^{\prime \prime} \).
New mAs at \( 56^{\prime \prime}= \) \( \qquad \)
c. You have completed an image using 25 mAs and \( 40^{\prime \prime} \) SID. Calculate the new mAs at a distance of \( 56^{\prime \prime} \).
New mAs at \( 56^{\prime \prime}= \) \( \qquad \)