Multiple Choice 1 point A light beam has a wavelength of 300 nm in a material of refractive index 1.5. In a material of refractive index 3.0, its wavelength will be 100 nm 300 nm 150 nm 600 nm
Added by Lisa W.
Close
Step 1
Step 1: The wavelength of light in a medium with refractive index $n$ is given by $$\lambda = \frac{\lambda_0}{n}$$ where $\lambda_0$ is the wavelength in vacuum. Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 98 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Adi S.
Light of wavelength 6000 Ă… travelling in vacuum enters a medium of refractive index $1.5 .$ The refracted beam has a wavelength of (a) $300 \mathrm{~nm}$ (b) $400 \mathrm{~nm}$ (c) $500 \mathrm{~nm}$ (d) $600 \mathrm{~nm}$
A light of wavelength $320 \mathrm{~nm}$ enters in a medium of refractive index $1.6$ from the air of refractive index $1.0$. The new wavelength of light in the medium will be $\mathrm{nm}$. (A) 520 (B) 400 (C) 320 (D) 200
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD