What is the equation of the line that is perpendicular to the line defined by the equation $2y = 3x + 1$ and goes through the point $(3, 2)$?
Added by Joaquin S.
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The equation of the given line is 2y = 3x + 1. We can rewrite this equation in slope-intercept form (y = mx + b) by dividing both sides by 2: y = (3/2)x + 1/2 From this equation, we can see that the slope of the given line is 3/2. Show more…
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