00:01
Hello student, in question number 35, the given n is 122 cells, sample size mean given is 3 .2 hour, standard deviation is 0 .1 and calculate the probability of x less than t lie between 3 to 3 .4 hour.
00:28
Let's find the probability and then we find the number.
00:30
Here we use the z statistics z1 minus mean 3 .2 upon sigma 0 .1 this comes to minus 2 and z2 is 3 .4 minus 3 .2 divided by 0 .1 this comes to 2.
00:59
Therefore, probability x lie between 3 to 3 .4 hour is equal to probability of z lie between minus 2 to 2.
01:10
Using standard normal distribution table, we get this value as 0 .9772 minus 0 .0228 that is probability of z less than 2 minus greater than minus 2 and this value comes 0 .9499.
01:32
So, the estimate number of batteries with the lifetime between 3 to 3 .4 that number is equal to probability 0 .94 probability of getting that number multiplied with total value and we get this number as 144 is given option.
01:52
In question number 56, i have to find using chabers theorem.
01:58
So, the theorem is given by probability of x minus mu less than or equal to 6 sigma is greater than or equal to 1 minus 1 by k square.
02:11
So, now we given the lower bound that is this bound is given 0 .75.
02:18
So, 1 minus 1 by k square this at least 75 percent that is 0 .75 all this value for k is greater than or equal to 0 .25 and we get the value of k as 2 k is at least 2.
02:42
So, according to chabers theorem 1 minus k square that is 1 minus 1 by 2 square is equal to 0 .75 percent of data say data value lie between second standard deviation that is two standard deviation we can say this equal to let's calculate the two deviation mu is given 560 sigma is given 80...