00:01
In this problem, we're looking at ir spectroscopy.
00:06
So remember, we can't take a chemical formula and give a structure from that, but if we're given structures with different functional groups, we're able to identify functional groups in the spectrum and determine which makes the most sense.
00:26
So you have four different structures to choose from.
00:30
And we have esters and a, b, and d are all esters.
00:50
A, c is a ketone.
01:01
All of them have an aromatic ring, so we're not surprised in our oop region from 2000 to 1600.
01:12
We see these little dips indicating we have those rings.
01:19
And we're also not surprised that around 1600, we see sharp peaks for double bonds between carbons because those aromatic rings have those double bonds.
01:40
So then we have to ask how can we determine which it is.
01:46
So one of the easiest ways to go about this is where does our carboneal absorbers show? so it's at 1712.
01:57
All right, so we have four a and d that are normal esters.
02:06
Those typically show up around 1740...