1. N = 6,000 and e = 1%
$n = rac{N}{1 + N(e)^2}$
$= rac{oxed{ ext{ }} }{1 + 6000 (0.01)

Question

1. N = 6,000 and e = 1%n$n = frac{N}{1 + N(e)^2}$n$= frac{boxed{text{ }} }{1 + 6000 (0.01)

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1. N = 6,000 and e = 1%\n$n = \frac{N}{1 + N(e)^2}$\n$= \frac{\boxed{\text{ }} }{1 + 6000 (0.01)^2}$\n$= \frac{6000}{1 + 6000(\boxed{\text{ }})}$\n$= \frac{6000}{1 + \boxed{\text{ }}} = \frac{6000}{\boxed{\text{ }}} = \boxed{\text{ }}$