00:01
Hello everyone, for this question we have to calculate the volume of stock solution required to add in each pcr reaction.
00:09
So, the stock solution required can be calculated by the formula volume of stock solution in microliters.
00:23
This will be equal to the desired concentration in nanomolar multiplied by pcr reaction volume in microliter.
00:46
This should be divided by the template concentration in nanomolar.
00:55
So, starting with the first pcr reaction, putting the values in the above formula, we will get the volume of stock solution equal to 500 nanomolars multiplied by 500 or 50 microliter divided by 525 microgram per microliter into 4500 base pairs multiplied by 660 gram per mole.
01:47
So, after calculating this, we get the volume of stock solution equal to 0 .141 microliters.
01:57
Now, further for second pcr reaction, volume of stock solution will be equal to 50 multiplied by 50.
02:21
This should be divided by 525 multiplied by again 400 base pairs and multiplied by 660 gram per mole.
02:31
So, the volume of second pcr reaction, it will be 0 .0138 microliters.
02:40
Now, for the third pcr reaction, the values will be volume of stock solution is equal to 0 .1 multiplied by 50 divided by 525 into 4500 multiplied by again 660...