Name 1 why are you instructed to read steps 2 5 before...

Name: ________________________________________ 1. Why are you instructed to read Steps 2-5 before going to the balance room? 2. What is the purpose of the aluminum foil skirt? 3. What is the purpose of the food support system? 4. Why is it important to keep the flame of the burning food from touching the bottom of the can? 5. A 1.520 g potato chip is completely combusted and the heat is absorbed by a 10.562 g aluminum soda can and skirt containing 200.0 g of water. The temperature increased from 10.0°C to 45.0°C. Calculate the heat of combustion of the potato chip in Cal./g.

Transcript

00:01 This problem we have two things to do and our first thing is to find the density of nitrogen gas at i'm going to go find a later font here at 27 degrees celsius which will be 300 and maybe i look at 300 .5 and 100 kilopascals and we're asked to do this in si units which i believe will be kilograms per meter cubed not exactly sure what they want for kilograms per meter cubed i usually use grams per liters for gases okay, let's begin.

01:22 We are going to use the following equation we're going to make these something.

01:26 This is an ideal gas so our density equal our pressure times our molar mass divided by r divided by t so our density will equal 100 kilopascals n2 has a molar mass of 28 .02 grams per mole.

02:00 We will divide that by 8 .314 l kpa per k mole and 300 .15 kelvin so my density here will be 100 times 28 .02 1 .4 divided by 300 .15 is 1 .12 grams per liter and to write number of sig figs that'll be one way that's hard 100 kilopascals has only one sig fig so the correct answer is one gram per liter but i'm going to go with 1 .23 grams per liter then i know that there are a thousand grams per kilogram and i know there are a thousand liters in a cubic meter so that'll cancel out and i'll get 1 .23 kilograms per cubic meter and to correct sig figs we have one point kilogram per meter cubed so i'll let you decide on sig figs here not sure what you want to do next we have a flue gas that is 40 % co2.

04:40 It is 6 .0 % o2 it is 80 % n2 the mixture is at 400 fahrenheit 765 millimeters of mercury find the partial pressures okay partial pressures let's start with our co2.

05:28 I have 14 point so this will be i'm going to change these two grams and a hundred gram sample and we're going to multiply this by 44 point zero grams per mole...

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