Name pid problem 1 10 points two parallel wires each carry a...

Name PID Problem 1: (10 points) Two parallel wires each carry a current of magnitude $I = 1.3 mA$; the current in the left wire goes into the page and the current in the right wire comes out of the page. The wires are separated by a distance $d = 4.2 cm$. The point P is an equal distance away from both wires. P I I a) Find the magnetic field (magnitude and direction) produced only by the left wire at the point P. [4 pts] $\frac{d}{2}$ $\frac{d}{2}$ $B_{left wire} =$ direction: Name PID c) A proton is released from rest at point P. Find the force experienced by the proton. [2 pt] $F=$ b) Find the overall magnetic field (magnitude and direction) at point P. [4 pts] $B_{overall} =$ direction:

Transcript

00:01 Two long straight wires are perpendicular to the page and separated by a distance g1 of 0 .8 centimeter.

00:06 Wire 1 carries 8 .3 ampere current into the page.

00:09 The magnetic field at point p at point p at a distance of d2 from the wire 2 is zero.

00:17 Here the magnetic field is zero.

00:20 A proton is at the midpoint between the two wires and traveling towards one wire with a velocity of 4 .6 times 10 raised to 7.

00:31 Meter per second over the magnitude of the force on the proton of the wire by the wire.

00:38 So first of all, because of this wire, the magnetic further direction of the magnetic field at p, using the right -hand rule, that's going to be over on the left because the thumb is pointing towards the current which is going into the page and the curl fingers are definitely curling like this.

00:57 So the tangent at this point is over on the left.

00:59 So let's call it b1.

01:00 So definitely if it is zero, then because of the wire 2 that has to be b2 but directed in this direction so definitely the current should come out of the page and magnitude is something which we can find so b1 should be equal to b2 i mean the magnitudes this means that mu not uh okay the current in the other wire is not yeah mu not i1 which is 8 .3 over 2 pi r where r is the distance of wire 1 from point p which is d1 plus d2.

01:35 What is d1, that's 0 .8.

01:38 The centimeter, what is d2? that's 4 .6 centimeter.

01:41 And that should be divided with, in fact, no need to divide because we are dealing over on the right side as well in terms of centimeter.

01:47 That will be mu not i by 2 pi r, where r is only d2, which is 4 .6.

01:54 Mu not and mu not is canceled.

01:56 2 pi and 2 pi is canceled.

01:57 So if you cross multiply, then 8 .3 times 4 .6 is equal to, this will become i think 5 .4 5 .4 times high and if we divide both sides by 5 .4 then 8 .3 times 4 .6 over 5 .4 that is the current and the current is coming as 7 .07 ampere that's the current.

02:22 That's not required that's not asked anywhere but it's a part of the question because we need to find this to answer what is asking the question now they're asking the magnitude of the proton uh the magnitude of the force on the proton...

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