00:01
Here the question is to name the given compounds.
00:04
So the first structure is as shown here.
00:08
So as you can see there is a cyclopentine group because there is a double bond here.
00:14
So the word root will be cyclopentinine and in this cyclopentine ring there are two medial groups.
00:23
Now numbering of this cyclic group can be done as 1, 2, 3, 4, 5.
00:32
If we write in the reverse order as 1, 2, 3, 4, 5, then the medial groups are present in 1st and 4th position, while in the first case it is 1st and 3rd position.
00:46
So the 1 with the lowest numbering is preferred.
00:50
So in the 1st and 3rd position we have 2 middle groups.
00:55
So di -medial.
00:57
So 1 3, die needle cyclopatin is the answer to this question.
01:03
The second structure given is ch3, ch2, double bond ch2, ch2, ch2, ch2, ch2, ch2, ch2, ch3.
01:15
So here the numbering can be done as 1, 2, 4, 5, 6, 7 or 1, 2, 3, 4, 5, 6, 7.
01:29
But here the numbering should be such a way that the alken should have the lowest number possible.
01:36
So this is the right way of numbering...