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Hi.
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So today we are going to look at question 28.40 from fourth edition of smith's organic chemistry.
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So the question asks us to put down the official projection and label each storage enic centre as our our ask for each of these eight compounds.
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So we'll start with heart.
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Okay, so first, the official projection sort of have coming here.
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I wanted to michael group here.
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Then we will have on the opposite side our roaming hydrogen and a carbon.
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I wanted to oxygen and they had jobs.
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Thank you.
01:05
Yeah.
01:06
So that is our fischer projection.
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So the next thing is to find this theragenics center, which is going to be, i reckon this is going to be a miss carbon here.
01:18
So this is this carbon is not, uh let me go.
01:24
And this carbon has three groups that are the same, so it can be a sterile genic center for that reason.
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So we're working with this center carbon, so the next thing to do is to prioritize the associated groups.
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So we're going to do that based on the atomic mass of the associated groups using secondary atoms like these.
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Oxygen's with these hydrogen to break ties so we can assign first priority to the grooming because it's obvious we can assign fourth priority to the hydrogen because it's the lightest.
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Now, these two carbons have the same atomic mass.
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So we need to look at the secondary atoms hit these hydrogen and oxygen to break the tie.
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So these oxygen's have higher atomic mass than these hydrogen.
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So this harmony so to and this curtain is number three.
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So from there, we then want to look again at the three dimensional model that we have in the book to look along the axis of this bond here, the bond between our stereo genetic center and the lowest priority group.
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So that will look like because we will have our carton.
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We are looking along this bond with hydrogen behind.
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Then we will have our bro made here.
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We will have our c o each there and we will have our metal here.
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And then if we go back to our priorities, we know that will mean is number one.
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We know that the cover of the oxygen's was number two and we know that the method is number three.
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So from now, if we follow along from 1 to 2 to three, we are going that way.
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And because this is counter clockwise, that means that this sterile genic center is as type.
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We'll do that because that's part of the answer.
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So this is our fischer projection.
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This is our stereo genic center, and it is s type.
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So now moving on to part b.
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So part b is a little bit smaller molecule, so it'll be a little easier to draw the fisher projection.
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But we're gonna do the same thing.
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So we have our carbon on to a chlorine on this side.
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A metal on this side.
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Hydrogen is a mall, fun to hydrogen here and a braid there.
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So that's our official projection.
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Now, this current can't be stereo center because it has 300 bits on it.
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So we are looking at this carbon, which means that then you do a side priority.
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So browning is the largest, so it gets one more.
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He's next, so it gets to carving is third and hydrogen is fourth.
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Now, looking back at the projection that we have in the book, if we kind of rotate that in our heads, we get our center carbon.
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We got grown in here.
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We get chlorine here and we get our muscle there.
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So then we put our priority labels back on here.
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123 same as we have over here.
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That gives us counterclockwise once again.
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So we go back to red.
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And that means that this is also an s type stereo center.
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So for part to see, we're looking at a much larger molecule this time, so i'm gonna give myself a little bit more supposed to work with.
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So this is the carbon that is separated in the book trying.
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So we have a method group on the side.
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We have a oxygen to another medical group here.
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Okay, we have an ethnic group here.
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Yeah, cleaned up a little bit.
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Oh, man, we have our oxygen through to another method group.
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Yeah, now that we've gotten that all drawn out, that is our fischer projection.
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So looking for stereo centers, this carbon is not an option.
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This carbon is not an option.
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This carbon is not an option saying that this this and this because they all have multiple hydrogen is causing them to be symmetric these oxygen's are not an option because they both have 23 pairs.
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So our only carbon that is a stereo center isn't this one.
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So assigning priority this one's a little more complicated because you have two sets of ties, so oxygen beats out carbon.
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So these oxygen's will be one and two.
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These carbons will be three and four.
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So between those ties, we have to go to the next.
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So oxygen goes up to this carbon and this carton again, we have a tie break.
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So this carbon expanded to three hydrogen while this carbon responded to two hydrogen and another carbon.
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So this one gets to be number one.
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I mean, this is number two, and we'll do the same for these two carbons.
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At three and four, this carbon is bonded to three hydrogen.
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Well, this carbons wanted to hydrogen and another carbon is that this carving is three and this carbon to sport.
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So now we can make our projection.
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We'll put this up here.
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We have our carbon in there.
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That is our stereo center carbon.
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Now, looking back at the three d model in the book, we want to look along the access towards this metal group with the metal group behind.
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So if we rotate that in our minds, i we have our methods are sorry.
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Ethel group here two.
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Yeah, ugly.
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We have that c h three up here we have our oxygen into metal group and here we have our oxygen into apple.
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So looking back at our priority, this is number one.
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That's number two and this is number three.
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So 1 to 2 to three, we are once again the counter clockwise, which means that this is that's type onto heart d part d.
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We have a we'll start with the furthest left carbon.
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So we have carving with three hydrogen ins to another carving to hide regions on to the carbon that is bought it to chlorine, hydrogen and grown in terms of finding our stereo center.
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It has to be this carbon because, as i said before, the carbons with multiple hydrogen are not able to be stereo centers due to symmetry.
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So now, assigning priority grooming gets the one or he gets to carbon gets three and hydrogen gets four because that is based on the atomic weights of those bernie being highest following down to hydrogen being smallest.
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So if we look at our projection, we want to look at the stairs center carbon looking down the carbon hydrogen on the hydrogen behind.
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So that gives us where are we here? our little group group here.
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And our chlorine there.
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So it is in those priorities.
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Back in, we have one, two, and three, which gives us counterclockwise and another s type continuing down to part e.
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We have this one a little nice.
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It's almost done for us.
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I'm going to rotate it 90 degrees clockwise to make it a little easier to fit on the page.
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So here we have the metal groups that in the book is on top on to carbon.
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Okay.
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There.
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Hi there.
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This is a coordinated carbon next on the other side.
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Okay, corn.
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And then this is our eco group.
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Focus on the bottom in the book.
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Okay, so now we're looking for stereo centers, which is going to be this carbon and this problem.
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They are both bonded to four different groups.
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So here we have brimming hydrogen metal and this longer chain, this one has hydrogen, chlorine and two different carbons.
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Different because of this brought me here.
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So we will start with the further left carbon.
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I'm gonna believe for this one.
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So this one gets for burning its first priority.
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Between these two carbons, we have to pick one, and then hydrogen will get lowest priority.
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So between these two carbons, this carbon expanded to three hydrogen.
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This carbon is bonded to a carbon, chlorine and hydrogen.
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So this one will get second priority, and this one will get third so down below, looking at our projection.
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So this is for our blue carbon.
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We are going to look along this bond.
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So we are looking at the bonds to the hydrogen now, which means that we are going to get our method here.
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We are going to get boil me here, and we are going to get the rest of the molecule.
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Yep.
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Two singing coach three.
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So we put our priorities back on.
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I mean, that's one...