Question

Naturally occurring zirconium exists as five stable isotopes: $^{90}Zr$ with a mass of 89.905 amu (51.45%); $^{91}Zr$ with a mass of 90.906 amu (11.22%); $^{92}Zr$ with a mass of 91.905 amu (17.15%); $^{94}Zr$ with a mass of 93.906 amu (17.38%), and $^{96}Zr$ with a mass of 95.908 amu (2.80%). Calculate the average mass of zirconium.

Name: Naturally occurring zirconium exists as five stable isotopes: ^90Zr with a mass of 89.905 amu (51.45%); $^{91}Zr$ with a mass of 90.906 amu (11.22%); $^{92}Zr$ with a mass of 91.905 amu (17.15%); $^{94}Zr$ with a mass of 93.906 amu (17.38%), and $^{96}Zr$ with a mass of 95.908 amu (2.80%). Calculate the average mass of zirconium.
Uploaded: 2022-07-26T09:25:17-08:00
Duration: 4 min 9 s
Channel: Adi S
Description: Naturally occurring zirconium exists as five stable isotopes: ^90Zr with a mass of 89.905 amu (51.45%); $^{91}Zr$ with a mass of 90.906 amu (11.22%); $^{92}Zr$ with a mass of 91.905 amu (17.15%); $^{94}Zr$ with a mass of 93.906 amu (17.38%), and $^{96}Zr$ with a mass of 95.908 amu (2.80%). Calculate the average mass of zirconium.

          Naturally occurring zirconium exists as five stable isotopes: $^{90}Zr$ with a mass of 89.905 amu (51.45%); $^{91}Zr$ with a mass of 90.906 amu (11.22%); $^{92}Zr$ with a mass of 91.905 amu (17.15%); $^{94}Zr$ with a mass of 93.906 amu (17.38%), and $^{96}Zr$ with a mass of 95.908 amu (2.80%). Calculate the average mass of zirconium.

$Naturally occurring zirconium exists as five stable isotopes: ^90Zr with a mass of 89.905 amu (51.45%); $^{91}Zr$ with a mass of 90.906 amu (11.22%); $^{92}Zr$ with a mass of 91.905 amu (17.15%); $^{94}Zr$ with a mass of 93.906 amu (17.38%), and $^{96}Zr$ with a mass of 95.908 amu (2.80%). Calculate the average mass of zirconium.$

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