Navigation A commercial jet airplane climbs at takeoff with slope $m=3 / 8 .$ How far in the horizontal direction will the airplane fly to reach an altitude of $12,000 \mathrm{ft}$ above the take- off point?
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Step 1: The slope of the airplane's climb is given as $m = 3/8$, which means $\tan(\theta) = 3/8$, where $\theta$ is the angle of climb. Show more…
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