00:01
Okay, so i see that you need help with this question.
00:02
So it's a sample size of 12, a mean of 48, and a standard deviation of 5.
00:08
Find the margin of error at an 80 % confidence interval.
00:13
So first thing you're going to do is 1 minus 0 .8, which is 0 .2.
00:19
1 minus 0 .2 divided by 2, and that is 0 .9.
00:27
And then you have t0 .9, a degrees of freedom of 11.
00:32
So that's 1 .36.
00:34
So that number is very important.
00:37
So then you're going to take 48 plus or minus 1 .36 times 5 over the square root of 12, 48 plus or minus 1 .36 times 1 .44, and then 48 plus or minus 1 .97.
00:55
And then we have a confidence interval of 46 .03 comma 49 .97.
01:05
Then it says find the critical value that corresponds to the confidence interval of 99%, 99 .9 % i should say.
01:24
So you're going to do 1 minus 0 .999 equals 0 .001.
01:32
1 minus 0 .001 divided by 2, and that is 0 .9995.
01:38
So that's a critical value.
01:45
Karen wants to advertise how many chocolate chips are in each.
01:50
Big chocolate chip at her bakery.
01:53
She randomly selects 48 cookies and finds the number of chocolate chips per cookie in the sample has a mean of 18 .4 and a standard deviation of 16.
02:06
And wants to know the 95 % confidence interval.
02:14
So you have an average of 48, a mean of 18 .4, a standard deviation of 16.
02:37
So then that's going to be 0 .95.
02:43
I'm sorry, 0 .999...