Question

Combustion (bomb) calorimeter. In an experiment, a 0.7868 g sample of nonanedioic acid (C9H16O4) is burned completely in a bomb calorimeter. The calorimeter is surrounded by 1.337 x 10^3 g of water. During the combustion the temperature increases from 24.73 to 27.67 °C. The heat capacity of water is 4.184 J · g^-1 · °C^-1. The heat capacity of the calorimeter was determined in a previous experiment to be 962.6 J · °C^-1. Assuming that no energy is lost to the surroundings, calculate the molar heat of combustion of nonanedioic acid based on these data. C9H16O4(s) + 11O2(g) -> 8H2O(l) + 9CO2(g) + Energy Molar Heat of Combustion = kJ/mol

          Combustion (bomb) calorimeter.

In an experiment, a 0.7868 g sample of nonanedioic acid (C9H16O4) is burned completely in a bomb calorimeter. The calorimeter is surrounded by 1.337 x 10^3 g of water. During the combustion the temperature increases from 24.73 to 27.67 °C. The heat capacity of water is 4.184 J · g^-1 · °C^-1.

The heat capacity of the calorimeter was determined in a previous experiment to be 962.6 J · °C^-1.

Assuming that no energy is lost to the surroundings, calculate the molar heat of combustion of nonanedioic acid based on these data.

C9H16O4(s) + 11O2(g) -> 8H2O(l) + 9CO2(g) + Energy

Molar Heat of Combustion = kJ/mol

Combustion (bomb) calorimeter.

In an experiment, a 0.7868 g sample of nonanedioic acid (C9H16O4) is burned completely in a bomb calorimeter. The calorimeter is surrounded by 1.337 x 10^3 g of water. During the combustion the temperature increases from 24.73 to 27.67 °C. The heat capacity of water is 4.184 J · g^-1 · °C^-1.

The heat capacity of the calorimeter was determined in a previous experiment to be 962.6 J · °C^-1.

Assuming that no energy is lost to the surroundings, calculate the molar heat of combustion of nonanedioic acid based on these data.

C9H16O4(s) + 11O2(g) -> 8H2O(l) + 9CO2(g) + Energy

Molar Heat of Combustion = kJ/mol

Added by Omonzogie O.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Supreeta N

03/06/2023

Step 1

337 x 10^3 g Specific heat capacity of water = 4.184 J/g°C Temperature difference = 27.67°C - 24.73°C = 2.94°C Using the formula Q = mcΔT, where Q is the heat released, m is the mass, c is the specific heat capacity, and ΔT is the temperature difference: Q = Show more…

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