00:01
To determine the rate law and the rate constant for this reaction, we'll look at first experiments 1 and 2.
00:08
We notice that in experiments 1 and 2 that the concentration of h2 is constant at 2 .49 molar, but the concentration of n2 going from experiment 2 to experiment 1 is increasing.
00:25
So only n2 increases, and it increases by a factor of, it goes to 2 .39 from 1 .07, which gives us an increase by a factor of 2 .23.
00:49
When that factor increase in concentration occurs, we get a rate that increases.
00:58
It increases.
01:02
By going to 0 .6 to 7 from 0 .1 to 6.
01:11
This is a factor increase of 4 .98.
01:23
So when we 2 .23 times the concentration, we 4 .98 the rate.
01:31
So what do we need to raise the concentration to, we 4 .98 the rate.
01:34
So what do we need to raise the concentration to? that factor increase in rate and that ends up being 2 .2 .23 raised to the 2 gives us 4 .98.
01:52
So that means it's second order.
02:01
Then if we look at experiments 1 and 3, the concentration of n2 is staying constant and only h2 increases.
02:17
It increases with if we look at experiment three compared to experiment one, it increases to 2 .49 from 0 .758...