Calculate the concentration of Ca$^{2+}$ when 50 mL of 0.005 M Ca$^{2+}$ is titrated with 0.01 M EDTA ($\alpha$ for EDTA at pH = 10 is 0.35) in a solution buffered to a constant pH = 10 when the volume of EDTA added is 25 mL. $K_f$ CaY$^{2-}$ = 5.0 x 10$^{10}$ (9 Marks)
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005 M Ca solution. Moles of Ca = concentration of Ca x volume of Ca solution Moles of Ca = 0.005 M x 0.050 L Moles of Ca = 0.00025 moles Show more…
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