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Hello everyone.
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Here we are given the graph where on y -axis we have position in meter.
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On x -exes, we have time in seconds.
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We have to find the v average.
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Firstly, when the object is going from zero meters to 50 meters, that is at zero seconds, it is at zero meter.
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And at five seconds, it is at 50 meters.
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Then we have to find the v average if, at 0 seconds, it is on 50 meters and then in 5 seconds it is at 0 meters.
00:37
That is, it's going in the opposite direction.
00:43
Now for part a, simply it will be the slope for these two points.
00:54
That is, the v average will be equal to x2 minus x1 divided by t2 minus t1.
01:12
So this is equal to x2, that is the distance...