00:01
The resistance r1 is equal to 8 kω, r2 is equal to 2 kω, rc is equal to 4 .7 kω, re is equal to 1 .2 kω, vcc is equal to 10 v.
00:28
Β varies from 10 v to 200 v.
00:37
The voltage at base is equal to r2 upon r1 plus r2 into vcc.
00:51
Substitute the values 2 kω divided by 2 kω plus 8 kω into 10 v.
01:03
This is equal to 2 v.
01:06
The total resistance rb is equal to r1 into r2 divided by r1 plus r2.
01:23
Substitute the values 2 kω into 8 kω divided by 2 kω plus 8 kω.
01:35
This is equal to 1 .6 kω.
01:38
Now applying kirchhoff's voltage loop rule at the base emitter loop, we have vb minus ib rb minus vbe, this is the base emitter voltage, minus ib, the base current plus the collector current into re.
02:23
This is equal to 0.
02:25
Now substitute the known values 2 v minus ib into 1 .6 kω minus 0 .7 v minus ib plus ic into 1 .2 kω equal to 0.
02:49
Hence 1 .3 v is equal to 2 .8 kω ib plus 1 .2 kω ic.
03:04
Now β is equal to ic divided by ib...