Question

Problem 14: Determine the value of the current $I_x$. A. 0.6 Amps B. 0.5 Amps C. 0.4 Amps D. 0.3 Amps E. 0.2 Amps $12I_x = 24 + 8I_x + 4I_x$ $12I_x - 24 - 4 = 8I_x$ $\frac{12I_x - 20}{8} = I_x$ $I_x = 12.025 - 8 + 4 = 0.6$ Problem 15: Determine the value of the voltage $V_{out}$ $V_{oc} = \frac{12}{0.07}$ $-V_{out} = I_{sc}$ $I_e = \frac{12}{0.07} V_{out} + \frac{-50 - 0.028}{0.07} = 0.1052 V$ A. -1.92 Volts D. -5.76 Volts B. -2.88 Volts E. -6.72 Volts C. -3.84 Volts

          Problem 14: Determine the value of the current $I_x$.
A. 0.6 Amps
B. 0.5 Amps
C. 0.4 Amps
D. 0.3 Amps
E. 0.2 Amps
$12I_x = 24 + 8I_x + 4I_x$
$12I_x - 24 - 4 = 8I_x$
$\frac{12I_x - 20}{8} = I_x$
$I_x = 12.025 - 8 + 4 = 0.6$
Problem 15: Determine the value of the voltage $V_{out}$
$V_{oc} = \frac{12}{0.07}$
$-V_{out} = I_{sc}$
$I_e = \frac{12}{0.07} V_{out} + \frac{-50 - 0.028}{0.07} = 0.1052 V$
A. -1.92 Volts
D. -5.76 Volts
B. -2.88 Volts
E. -6.72 Volts
C. -3.84 Volts

Problem 14: Determine the value of the current Ix.
A. 0.6 Amps
B. 0.5 Amps
C. 0.4 Amps
D. 0.3 Amps
E. 0.2 Amps
12Ix = 24 + 8Ix + 4Ix
12Ix - 24 - 4 = 8Ix
(12Ix - 20)/(8) = Ix
Ix = 12.025 - 8 + 4 = 0.6
Problem 15: Determine the value of the voltage Vout
Voc = (12)/(0.07)
-Vout = Isc
Ie = (12)/(0.07) Vout + (-50 - 0.028)/(0.07) = 0.1052 V
A. -1.92 Volts
D. -5.76 Volts
B. -2.88 Volts
E. -6.72 Volts
C. -3.84 Volts

Added by Diane G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Suman K

Step 1

We are given the equation hr + h2 = 1Z1. This equation is not clear and seems to be missing some information. Without more information, we cannot solve for hr or h2. Show more…

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Thank you!! A. 70.6 Amps B. 0.5 Amps C. 0.4 Amps D. 0.3 Amps E. 0.2 Amps hr + h2 = 1Z1 24V U8 121 XIa = 1 - H2 - x121 1Z - ZO sdx 3 Ix = IZ.uZS - 6 + 4 = 6.U Problem 15: Determine the value of the voltage Vout 69 WW 12V V 8 Vout 0.07V Vee Vat = Isc 0.07 L'O xe - 384V A. -1.92 Volts B. -2.88 Volts -3.84 Volts D. -5.76 Volts E. -6.72 Volts