Question

5. •• CP Consider the circuit shown in Fig. P25.70. The battery has emf 72.0 V and negligible internal resistance. $R_2 = 2.00 \Omega$, $C_1 = 3.00 \mu F$, and $C_2 = 6.00 \mu F$. After the capacitors have attained their final charges, the charge on $C_1$ is $Q_1 = 18.0 \mu C$. What is (a) the final charge on $C_2$; (b) the resistance $R_1$? Figure P25.70 $R_1$ $R_2$ $C_1$ $C_2$

          5.
•• CP Consider the circuit shown in Fig. P25.70. The battery has emf 72.0 V and
negligible internal resistance. $R_2 = 2.00 \Omega$, $C_1 = 3.00 \mu F$, and $C_2 = 6.00 \mu F$. After the
capacitors have attained their final charges, the charge on $C_1$ is $Q_1 = 18.0 \mu C$. What is
(a) the final charge on $C_2$; (b) the resistance $R_1$?
Figure P25.70
$R_1$
$R_2$ $C_1$ $C_2$

5.
•• CP Consider the circuit shown in Fig. P25.70. The battery has emf 72.0 V and
negligible internal resistance. R2 = 2.00 Ω, C1 = 3.00 μ F, and C2 = 6.00 μ F. After the
capacitors have attained their final charges, the charge on C1 is Q1 = 18.0 μ C. What is
(a) the final charge on C2; (b) the resistance R1?
Figure P25.70
R1
R2 C1 C2

Added by Derrick G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

12/17/2022

Step 1

Q2 = (6.00μF / 3.00μF) * 18.0μC Q2 = 2 * 18.0μC Q2 = 36.0μC Show more…

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negligible internal resistance. R_(2)=2.00Omega ,C_(1)=3.00mu F, and C_(2)=6.00mu F. After the capacitors have attained their final charges, the charge on C_(1) is Q_(1)=18.0mu C. What is (a) the final charge on C_(2); (b) the resistance R_(1) ? Figure P25.70 5. CP Consider the circuit shown in Fig.P25.70.The battery has emf 72.0V and negligible internal resistance.R=2.00,C=3.00F,and C=6.00F.After the capacitors have attained their final charges,the charge on C is Q = 18.0 C.What is a)the final charge on C2;(b)the resistance R Figure P25.70 RI T R2 CC