00:02
Hi there.
00:03
In this question, we are being asked about two potential double replacement reactions.
00:14
And i say potential because there's a possibility of no reaction occurring.
00:20
All right.
00:21
So in a double replacement, what happens is we have two ionic aquaous solutions.
00:28
And they exchange ions.
00:30
So the positive ion from the first goes with the negative ion from the second.
00:34
And the positive ion from the second goes with the negative ion from the first.
00:39
To have a reaction, one of the new products must be insoluble.
00:50
It must form a precipitate.
00:57
It is possible that they could produce water or a gas, and that would also be considered a reaction.
01:06
But for the reactions we're working with here, we are just looking for a precipitate.
01:13
So one of the products must form a precipitate to have a reaction.
01:20
If there is no precipitate, if they both just remain soluble, there's no reaction.
01:25
All right, well, with that in mind, let's look at our two combinations here, one at a time.
01:32
The first one, we have copper two nitrate.
01:35
So that's going to be cu, n -o -3, 2, and that's aquas, and that is reacting with sodium sulfate, n -a -2 -s -o -4, also aquas.
01:51
So they are going to exchange ions.
01:54
The copper two is going to go with the sulfate, forming c -u -s -o -4, and the sodium will go with the nitrate.
02:09
If we need to write an equation for this, we would need to balance this by putting a two here.
02:14
But we don't know if we have a reaction yet.
02:16
We need to look at the solubility rules to determine if either of these new products forms of precipitate.
02:27
So first of all, the copper sulfate, the copper two sulfate.
02:30
As we look at the solubility rules for that, we see that it is soluble.
02:35
In other words, it's still going to remain dissolved or be aquaous...