00:01
Okay, so for this problem, the question is how many moles of gas there are, given that this gas is cooled under with the constant pressure, and then it asks for the same thing, assuming constant volume.
00:17
Let me see if there's anything more to that.
00:21
Let's then change in internal.
00:23
Yeah, so first, just to kind of sum, first we want to find the number of moles in the gas.
00:29
So you want to use the formula that q is ncp delta t.
00:44
And then this delta t is 40 kelvin, also 40 celsius.
00:52
But since you convert celsius to kelvin by adding 273, if you subtract your different values, the 273 kind of subtracts out.
01:00
So the conversion is the same and hopefully you've seen that elsewhere.
01:05
And so if we do that, we have our cp, now we have our delta t, and we have our q.
01:12
So you can just say that n is q divided by cp, delta t.
01:20
And if you plug in the numbers i have listed on the left hand panel, you'll get, maybe you'll get what i got, which was that there's 21 .5 moles, which is kind of a lot of gas.
01:37
Great.
01:38
And for part b, it asks for delta u.
01:44
So delta u is equal to ncv delta t, even though it's not a constant volume process.
01:55
It's always ncv, delta t.
01:57
And there's like an explanation in the book if you want to read it.
02:00
But i mean, it's just kind of all constructed that way.
02:03
So if you use this for your n, your cv here, which just comes from the table in the book, and your delta t is 40.
02:12
Calvin, perhaps you will get what i got, which is minus 17, oops, minus 17 ,900 jewels.
02:26
I'm just going to go with three sighings here.
02:28
And for part c, it asks for the work...