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work Section 2.2 < Evaluate the piecewise function at the given values of the independent variable. $\begin{cases} 2x+5 & \text{if } x<0\\ 2x+6 & \text{if } x\ge 0 \end{cases}$ (a) f(-1) (b) f(0) (c) f(1) (a) f(-1) = Question 10, 2.2.53 Part 1 of 3

          work Section 2.2
<
Evaluate the piecewise function at the given values of the independent variable.
$\begin{cases} 2x+5 & \text{if } x<0\\ 2x+6 & \text{if } x\ge 0 \end{cases}$
(a) f(-1)
(b) f(0)
(c) f(1)
(a) f(-1) = 
Question 10, 2.2.53
Part 1 of 3
        
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work Section 2.2
<
Evaluate the piecewise function at the given values of the independent variable.
2x+5    if  x<0
 2x+6    if  x≥ 0
(a) f(-1)
(b) f(0)
(c) f(1)
(a) f(-1) = 
Question 10, 2.2.53
Part 1 of 3

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Nork Section 2.2 Question 10, 2.2.53 Evaluate the piecewise function at the given values of the independent variable. f(x)={(2x+5 if x<0),(2x+6 if x>=0):} (a) f(-1) (b) f(0) (c) f(1) (a) f(-1)= Question 10,2.2.53 Part1of3 vork Section 2.2 Evaluate the piecewise function at the given values of the independent variable KK 2x+5ifx<0 f(x)= 2x+6ifx0 af-1 b)f(0) cf(1 af-1=
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Transcript

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00:01 I'm given a piecewise function, which is just a function that's defined for different values for different inputs.
00:09 So the function is going to equal negative 3 if x is less than or equal to 0.
00:18 The function is going to equal 2x minus 2 if x is greater than or equal to 0.
00:27 Sorry, this is less than 0.
00:29 Now, if you think about what the graph of this function would look like, at 0, i'm going to have a hole at negative 3, and then just a horizontal line through negative 3, because all values less than 0 equal negative 3...
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