Question

Not Drawn to Scale In the diagram, \( P Q R \) is an equilateral triangle of side \( 18 \mathrm{~cm} . \bar{M} \) is the midpoint of \( \overline{Q R} \). An are of a circle with centre \( P \) touches \( \overline{Q R} \) at \( M \) and meets \( \overline{P Q} \) at \( A \) and \( \overline{P R} \) at \( B \). Calculate, correct to two decimal places, the area of the shaded region. Take \( \pi=\frac{22}{7} \) ]

          Not Drawn to Scale
In the diagram, \( P Q R \) is an equilateral triangle of side \( 18 \mathrm{~cm} . \bar{M} \) is the midpoint of \( \overline{Q R} \). An are of a circle with centre \( P \) touches \( \overline{Q R} \) at \( M \) and meets \( \overline{P Q} \) at \( A \) and \( \overline{P R} \) at \( B \). Calculate, correct to two decimal places, the area of the shaded region.
Take \( \pi=\frac{22}{7} \) ]

Not Drawn to Scale
In the diagram, P Q R is an equilateral triangle of side 18 cm . M̅ is the midpoint of Q R. An are of a circle with centre P touches Q R at M and meets P Q at A and P R at B. Calculate, correct to two decimal places, the area of the shaded region.
Take π=(22)/(7) ]

Added by Kenneth P.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

Instant Answer

Solved by Expert Sheryl Ezze

Step 1

The triangle \(PQR\) is equilateral with side length \(18 \, \text{cm}\). \(M\) is the midpoint of \(\overline{QR}\), so \(QM = MR = 9 \, \text{cm}\). Show more…

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Not Drawn to Scale In the diagram, \( P Q R \) is an equilateral triangle of side \( 18 \mathrm{~cm} . \bar{M} \) is the midpoint of \( \overline{Q R} \). An are of a circle with centre \( P \) touches \( \overline{Q R} \) at \( M \) and meets \( \overline{P Q} \) at \( A \) and \( \overline{P R} \) at \( B \). Calculate, correct to two decimal places, the area of the shaded region. Take \( \pi=\frac{22}{7} \) ]