Note that this exercise represents a completely imaginary situation. Suppose that a statistics class contained exactly 8 men and 8 women. You have discovered that the teacher decided to assign 5 Fs on an exam by randomly selecting names from a hat. He concluded that this would be easier than actually grading all those papers and that his students are all equally skilled in statistics—but someone has to get an F. What is the probability that all 5 Fs were given to male students?
Added by Lisa T.
Step 1
This can be calculated using combinations: $$\binom{16}{5} = \frac{16!}{5!(16-5)!} = \frac{16!}{5!11!} = 4368$$ Now, we need to find the number of ways to select all 5 male students from the 8 male students. This can also be calculated using Show more…
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Note that this exercise represents a completely imaginary situation. Suppose that a statistics class contained exactly 8 men and 8 women. You have discovered that the teacher decided to assign 5 Fs on an exam by randomly selecting names from a hat. He concluded that this would be easier than actually grading all those papers and that his students are all equally skilled in statistics-but someone has to get an F. What is the probability that all 5 Fs were given to male students?
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Note that this exercise represents a completely imaginary situation. Suppose that a statistics class contained exactly 8 men and 8 women. You have discovered that the teacher decided to assign $5 \mathrm{Fs}$ on an exam by randomly selecting names from a hat. He concluded that this would be easier than actually grading all those papers and that his students are all equally skilled in statistics-but someone has to get an $\mathrm{F}$. What is the probability that all 5 Fs were given to male students?
A history class is comprised of 8 female and 6 male students. If the instructor of the class randomly chooses 9 students from the class for an oral exam , what is the probability that 5 female students and 4 male students will be selected? Round your answer to 3 decimal places.
Joanna Q.
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