NOTE: This is a multi-part question. Once an answer is...

NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Two forces P and Q are applied as shown to an aircraft connection. Problem 02.051.b - Find tensions using equations of equilibrium Knowing that the connection is in equilibrium and that P = 645 lb and Q = 800 lb, determine the tension in rods A and B The tension in rod A is lb. The tension in rod B is lb.

Transcript

00:01 In this problem, you have an aircraft connection, and it's got forces p and q that you know, and f, a, and fb that you're looking for.

00:14 And you're told this object is in equilibrium.

00:18 So let's do a traditional x, y, axes, nothing, no reason to be fancy.

00:24 And then we just break every force known and unknown into components.

00:32 F net x.

00:34 We have q and it's making a 40 degree angle with the vertical.

00:39 So this would be the x, positive x component, but we're using sign.

00:45 So q, sign 40 degrees.

00:50 Now we got fa that is gonna be a negative x component using cosine 50, minus f a cosine 50 degrees.

01:05 And then we have fb.

01:07 Just horizontal so plus fb in the positive x direction equals zero so it's equation one if you're having difficulties with breaking these up into components just redraw each one with its tail at the origin so here's the 50 degrees so this is f a so you can see the cosine you know you could it's always better to put it on a separate axes and you'd have q here here's your 40 degrees, this is q, and you can see that the x is going to be with the sign.

01:48 If you're ever in doubt, do that.

01:52 So that's equation one.

01:55 We know q, we obviously know the angles.

01:58 We don't know f, a, f, a, f, b.

01:59 So we've got one equation, 2, or no.

02:01 So we've got to go elsewhere.

02:02 So we go to the other equilibrium equation, f, net y...

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