Question

The per phase average power of the load for a balanced Y-Y circuit is 1000 (W) at a leading power factor of 0.8. If the magnitude of the line current is 15 (A) rms, then the magnitude of the phase voltage, in V, is equal to:

Name: The per phase average power of the load for a balanced Y-Y circuit is 1000 (W) at a leading power factor of 0.8. If the magnitude of the line current is 15 (A) rms, then the magnitude of the phase voltage, in V, is equal to:
Uploaded: 2023-12-03T19:16:23-08:00
Duration: 2 min 21 s
Channel: Supreeta N
Description: The per phase average power of the load for a balanced Y-Y circuit is 1000 (W) at a leading power factor of 0.8. If the magnitude of the line current is 15 (A) rms, then the magnitude of the phase voltage, in V, is equal to:

          The per phase average power of the load for a balanced Y-Y circuit is 1000 (W) at a leading power factor of 0.8. If the magnitude of the line current is 15 (A) rms, then the magnitude of the phase voltage, in V, is equal to:

The per phase average power of the load for a balanced Y-Y circuit is 1000 (W) at a leading power factor of 0.8. If the magnitude of the line current is 15 (A) rms, then the magnitude of the phase voltage, in V, is equal to:

Added by Abigail C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

12/03/2023

Step 1

Step 1: The formula for calculating the per phase average power in a balanced Y-Y circuit is P = √3 * Vph * Iph * cos(θ), where P is the power, Vph is the phase voltage, Iph is the phase current, and θ is the phase angle. Show more…

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Notice the per phase avg power The per phase average power of the load for a balanced Y-Y circuit is 1000 (W) at a leading power factor of 0.8. If the magnitude of the line current is 15 (A) rms,then the magnitude of the phase voltage.in V,is equal to: