Q.3 The capsicum molecule is shown below, and one...

Q.3 The capsicum molecule is shown below, and one tetrahedral center has been identified. Use arrows to identify three other centers and identify the molecular geometry of each one. You must choose centers that all have different molecular geometry from each other, and you may NOT use another tetrahedral center. tetrahedral center Q.4 Two structural formulas for C2H4O2 were provided at the beginning of this document. Draw a third structural formula of C2H4O2. Q.5 Although BH3 and CH2O have similar shapes, one is polar and the other is non-polar. Explain why. Q.6 By now you should realize that having a Lewis structure showing an octet of electrons on a central atom is critical for stable molecules. Draw a Lewis structure for NO and NO2. Then predict whether they are stable or unstable and WHY.

Transcript

00:01 Hello, in the first part we need to find out the all the possible tetrahedral center.

00:06 So here we have the molecule as.

00:09 So here we need to find out this tetrahedral center.

00:13 Tataradral center means in a tetrahedral molecular geometry a central atom it is located at the center with four substituent that are located at the center of a tetrahedral.

00:25 That means the bond angle there it should be 1 .0.

00:30 0 .9 .5 degrees celsius when all four substituents are same for example as in methane.

00:39 So here in the tetrahedral carbon atom which is bonded to a different substituents in asymmetric carbon or it may be bonded with the same atom same atoms.

00:54 That means which typically leads to a chiral molecule if the four different substituents will here.

00:59 So as we can see here that is this carbon it is having this carbon and this carbon and it is having this and nitrogen and hydrogen and hydrogen that means sp3 hybridized carbon we can say that.

01:11 So this is again a tetrahedral center.

01:16 This carbon it is also a tetrahedral carbon or tetrahedral center and this carbon it is also a tetrahedral center.

01:29 Now we have the molecule that is c2h4 o we need to find out the structure of this.

01:38 Molecule that is possible structure so here we have that is c plus 1 minus h divided by 2 so here this carbon is 2 plus 1 hydrogen is 4 divided by 2 and this will become 3 minus 2 that is equal to 1 so hence 1 pi bond it is present or we can say 1 ring is present in this compound molecule as this carbon is true therefore ring is not possible or some kind of epoxy side we can it kind be possible so therefore the possible structure of this that is first is two carbon it is there one and two carbon c s3 c double bond o and h it is there that is one ld head group it is possible second possibility is that is if this is alkenes ch2 double bond, ch oh it is there...

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