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Now, assume that charge $q_2$ is negative; $q_2 = -6 \text{ nC}$, as shown in (Figure 2). What is the x-component of the net electric field at the origin, point O? Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive.

          Now, assume that charge $q_2$ is negative; $q_2 = -6 \text{ nC}$, as shown in (Figure 2). What is the x-component of the net electric field at the origin, point O?
Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive.
        
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Now, assume that charge q2 is negative; q2 = -6  nC, as shown in (Figure 2). What is the x-component of the net electric field at the origin, point O?
Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Now, assume that charge q_(2) is negative; q_(2)=-6nC, as shown in (Figure 2). What is the x-component of the net electric field at the origin, point O ?\nExpress your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive. Now, assume that charge q2 is negative; q2=--6 nC, as shown in (Figure 2). What is the x-component of the net electric field at the origin,point O? Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive.
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Transcript

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00:01 We're going to have a very similar situation to one of the previous problems that we just solved.
00:05 And in this case, the only difference is going to be the sign of the charges.
00:09 So we are told to find what is going to be the electric field on the x -axis coming from each of the charges presented on the figure over here.
00:20 So in order to begin, let's sketch what are going to be the direction of the fields at the origin coming from q1 and from q2.
00:28 From q1 we're going to have a field that is going towards the left remember that whenever we have electric fields we're going to treat them as if we had a positive charge at the origin and the direction of the field is the direction of which the particle would be repelled or attracted to and over here from q2 since the charge is negative the direction of the field is going to be the same and actually it's going to be of a larger magnitude because we have a much smaller distance compared to the other one.
01:02 Notice that both of them are going to be on the negative x direction so what we're going to get is that the net field is going to be equal to the sum of e1 plus e2...
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