00:01
Hello students, as we know the formula of e is equals to m c square where e is the energy m is the mass and c is the speed of light.
00:09
And we know mass of hydrogen, mass of hydrogen is equal to mass of proton, that is mass of proton and which is equals to 1 .673 multiplied by 10 -dhs to the power of minus 27 k -g.
00:24
And mass of sun is mass of sun is equals to 1 .989 multiplied by 10 dash to the power of 30 kj.
00:34
Now we know composition of sun, composition of sun, composition of sun is about 91 .2 % of hydrogen given by number of atoms.
00:51
And it is given that the conversion of 4 hydrogen atoms to 1 helium atoms result in the conversion of about 0 .0862 times the mass of proton.
01:03
Therefore we can say m is equal to 0 .02862 multiplied by mass of proton.
01:11
This is the total amount of mass of hydrogen converted to energy.
01:15
Now substitute mass of proton value we will get m is equals to 0 .0202.
01:21
2862 multiplied by 1 .673 multiplied by 10 ratio of the power of minus 27 kg and by multiplying this will be equal to 4 .788 multiplied by 10 ratio of power of minus 29 kages now total number of atoms in sun total number of atoms in sun total number of atoms in sun will be equals to mass of sun divided by mass of hydrogen divided by mass of hydrogen now substitute the value of mass of sun and mass of hydrogen as given below therefore this will be equal to this will be equals to 1 .989 multiplied by 10 to the power of 30 divided by 1 .673 multiplied by 10 dash to the power of minus 27 and by dividing this will be equals to 1 .188 880 8 multiplied by 10 ratio of power of 57 since the composition of sun is about 91 .2 % of hydrogen...