00:01
So, here is sodium carbonate.
00:03
Sodium carbonate.
00:04
So what is the formula of sodium carbonate? n82 -c -o -3.
00:09
So this sodium carbonate, it is required as decahydrate.
00:14
It is recovered as decahydrate from 1 ,000 kays of 5 % solution of sodium carbonate.
00:24
1 ,000 kaiser 5 % solution of sodium carbonate in water.
00:28
So, if 95 % of nda to c -o -3, it is recovered as deca hydrate, it is recovered as deca hydrate by cooling to 278 kelvin's.
00:48
So then we have to determine what is the mass of water that is evaporated.
00:54
Mass of water that is evaporated.
00:59
So, what a mass of water that is evaporated? so, here they have given mass of, mass of solution.
01:22
So, what is the mass of feed solution? that is, thousand case.
01:30
And that is, what is the mass fraction of, mass fraction of 202 -3 in the feed solution? that will be xf so that is 0 .05 so whenever we see mass of nd2 c43 in field so that is f m f a that is equal to xf b into mf so that is 0 .05 in 2000 that is equal to 50 kc that is given by 50 kc so whenever we calculate x f a into uf so that is that is equal to 0 .95 into so that is equal to 0 .05 0 .05 into 1000 that is equal to 50 kays.
02:38
So, if you're on 95 % of nda to 0 .03 it is recovered as crystals.
02:45
So what is the mass of nda to what is the mass of n -a -2 -c -03 that is mca that is 0 .95 into mfa that is equal to 0 .95 into 50 that is 47 .5 case that is equal to 47 .5 kiz.
03:12
So if one more of crystals of n .a .2 c .o .3 it has 10 mons of water.
03:21
Because why it is deca hydrate d .o3 10 h2o3 dacohydac.
03:29
So molar mass of ng to 03, molar mass of nda2 1 oxides and molar mass of water, molar mass of water, that is mp that is 18.
03:46
So nj2 -10h2o, the sodium co -ponent decahydride.
03:52
So 1 mole it consists of 1 mole of n .a...