Question

Q. An electrical engineer suggested the modified defibrillator circuit shown below. The inductor is meant to 'smooth out' the current through the chest during defibrillation, and yield a lower value of $P_{max}$ for a given dose. $R_{th} = 10k\Omega$ S D L 000 $v_s$ + $C = 20\mu F$ $R_{chest} = 500\Omega$ (a) Find the value of L that yields critical damping. We'll use this value of L in parts b and c. (b) Find $v_s$ so that the dose is 100J. You can assume the capacitor is fully charged when the switch is thrown to 'D'. (c) Suppose $v_s$ is equal to the value found in part b. What is the maximum power $P_{max}$ dissipated in the patient's chest during defibrillation?

          Q. An electrical engineer suggested the modified defibrillator circuit shown below. The inductor is meant to 'smooth out' the current through the chest during defibrillation, and yield a lower value of $P_{max}$ for a given dose.
$R_{th} = 10k\Omega$
S D
L
000
$v_s$ + 
$C = 20\mu F$
$R_{chest} = 500\Omega$
(a) Find the value of L that yields critical damping. We'll use this value of L in parts b and c.
(b) Find $v_s$ so that the dose is 100J. You can assume the capacitor is fully charged when the switch is thrown to 'D'.
(c) Suppose $v_s$ is equal to the value found in part b. What is the maximum power $P_{max}$ dissipated in the patient's chest during defibrillation?

Q. An electrical engineer suggested the modified defibrillator circuit shown below. The inductor is meant to 'smooth out' the current through the chest during defibrillation, and yield a lower value of Pmax for a given dose.
Rth = 10kΩ
S D
L
000
vs +
C = 20μ F
Rchest = 500Ω
(a) Find the value of L that yields critical damping. We'll use this value of L in parts b and c.
(b) Find vs so that the dose is 100J. You can assume the capacitor is fully charged when the switch is thrown to 'D'.
(c) Suppose vs is equal to the value found in part b. What is the maximum power Pmax dissipated in the patient's chest during defibrillation?

Added by Daniela F.

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