Object A of mass 10 kg is moving at a velocity 10 m/s to the right. It collides and sticks to object B of mass 10 kg moving in the same direction as object A with a velocity of 5 m/s. What is the final velocity with which the two objects are moving together ?
Added by Heather S.
Step 1
This is known as the law of conservation of momentum. The momentum of an object is calculated by multiplying its mass by its velocity. So, the total momentum before the collision is: Momentum of object A + Momentum of object B = (10 kg * 10 m/s) + (10 kg * 5 Show more…
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A $10 \mathrm{~kg}$ object collides with stationary $5 \mathrm{~kg}$ object and after collision they stick together and move forward with velocity $4 \mathrm{~ms}^{-1}$. What is the velocity with which the $10 \mathrm{~kg}$ object hit the second one? (a) $4 \mathrm{~ms}^{-1}$ (b) $6 \mathrm{~ms}^{-1}$ (c) $10 \mathrm{~ms}^{-1}$ (d) $12 \mathrm{~ms}^{-1}$
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Round 2
A 50 kg object is moving to the right with a speed of 10 m/s when it collides with a 20 kg object that is moving to the left with a speed of 4 m/s. The two objects stick together during the collision. Which of the following best describes the motion of the two objects after they collide? stationary (v=0) moving to the left at a speed greater than 10m/s moving to the left at a speed less than 10m/s moving to the right at a speed greater than 10m/s moving to the right at a speed less than 10m/s
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Two objects, $A$ and $B$, collide. A has mass $2.0 \mathrm{~kg}$, and $B$ has mass $3.0 \mathrm{~kg}$. The velocities before the collision are $\overrightarrow{\mathbf{v}}_{\mathrm{iA}}=$ $(15 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(30 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$ and $\overrightarrow{\mathbf{v}}_{\mathrm{i} B}=(-10 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(5.0 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$ After the collision, $\overrightarrow{\mathbf{v}}_{\mathrm{fA}}=(-6.0 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(30 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$. What is the final velocity of $B$ ?
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