Question

Obtain the Norton equivalent at terminals a-b of the circuit in the following figure if $R_1 = 12 k\Omega$ and $R_2 = 54 k\Omega$. $R_N = \boxed{}$ $k\Omega$ $I_N = \boxed{}$ $mA$

Name: obtain the norton equivalent at terminals a b of the circuit in the following figure if r1 12 komega and r2 54 komega rn boxed komega in boxed ma 25602
Uploaded: 2022-01-03T02:20:26-08:00
Duration: 1 min 44 s
Channel: Ameer Said
Description: obtain the norton equivalent at terminals a b of the circuit in the following figure if r1 12 komega and r2 54 komega rn boxed komega in boxed ma 25602

          Obtain the Norton equivalent at terminals a-b of the circuit in the following figure if $R_1 = 12 k\Omega$ and $R_2 = 54 k\Omega$.
$R_N = \boxed{}$ $k\Omega$
$I_N = \boxed{}$ $mA$

obtain the norton equivalent at terminals a b of the circuit in the following figure if r1 12 komega and r2 54 komega rn boxed komega in boxed ma 25602

Added by Teresa M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ameer Said

01/03/2022

Step 1

To do this, we short-circuit the voltage source and open-circuit the current source. Then, $R_N$ is the equivalent resistance seen from terminals a-b. $R_N = R_1 || R_2 = \frac{R_1 R_2}{R_1 + R_2} = \frac{12k\Omega \times 54k\Omega}{12k\Omega + 54k\Omega} = Show more…

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Obtain the Norton equivalent at terminals a-b of the circuit in the following figure if $R_1 = 12 k\Omega$ and $R_2 = 54 k\Omega$. $R_N = \boxed{}$ $k\Omega$ $I_N = \boxed{}$ $mA$