00:01
Hello students, in this question given as the circuit and the source voltage is given as 10 into cos of 10000 t, 10000 t plus 53 .1 degree, 53 .1 degree volt.
00:21
Now in this question we can write as the omega angular frequency is equal to the 10000 or we can 10 to the power 4 radian per second and now let us consider that at this node the voltage is v and at this node the voltage will be the maximum voltage of vs which is 10 volt.
00:53
Now this is equal to the 10 volt.
00:57
Next we will calculate the xl is equal to react impedance along the reactance.
01:15
So this will be equal to the omega l.
01:18
Now this is equal to the omega means 10 to the power 4 into l is 200 microhenry minus 6.
01:28
Now this will be equal to the 2 ohm.
01:30
Similarly xc is equal to 1 upon omega c.
01:35
Now this will be equal to the 1 upon 10 to the power 4 into 25 into 10 to the power minus 6.
01:45
So after calculation this will be equal to the 4 ohm.
01:55
Now in this circuit we can see that when the 3 i2 current is coming from this and i current is going in the reactor then remaining current i by 2 will come in the capacitor.
02:13
Now at this point is the zero volt.
02:16
This is the negative.
02:18
Now according to the reactance arm we can see that the current is equal to voltage upon resistance.
02:26
Voltage is voltage will be 10 minus v upon the resistance xl.
02:36
Now this will be equal to the 10 minus v upon 2...